Program to find Armstrong
Program to find Armstrong Number between 1 to 500
An Armstrong number or Narcissistic number is a n digit number such that the sum of its digits raised to the nth power is equal to the number itself.
For example, Let's take an armstrong number:
153
, which is 3 digit number, here 13 + 53 + 33
is 1 + 125 + 27
which is equal to 153.
Below is a program to find armstrong numbers between 1 to 500.
#include<stdio.h>
#include<math.h>
int main()
{
printf("\n\n\t\tStudytonight - Best place to learn\n\n\n");
int n,sum,i,t,a;
printf("\n\n\nThe Armstrong numbers in between 1 to 500 are : \n\n\n");
for(i = 1; i <= 500; i++)
{
t = i; // as we need to retain the original number
sum = 0;
while(t != 0)
{
a = t%10;
sum += a*a*a;
t = t/10;
}
if(sum == i)
printf("\n\t\t\t%d", i);
}
printf("\n\n\n\n\t\t\tCoding is Fun !\n\n\n");
return 0;
}
Output:
Program to check whether a number is Armstrong Number
Below is a program to check whether a number is armstrong or not.
#include<stdio.h>
#include<math.h>
int main()
{
printf("\n\n\t\tStudytonight - Best place to learn\n\n\n");
int n, sum = 0, c, t, a;
printf("Enter a number: ");
scanf("%d", &n);
t = n; // as need to retain the original number
while(n != 0)
{
a = n%10;
sum += a*a*a;
n = n/10;
}
printf("\n\n\n\t\t\tsum = %d", sum);
if(sum == t)
printf("\n\n\t\t%d is an armstrong number\n", t);
else
printf("\n\n\t\t%d is not an armstrong number\n", t);
printf("\n\n\n\n\t\t\tCoding is Fun !\n\n\n");
return 0;
}